Motion with Constant Acceleration

The figure shows the $v-t$ graph of a particle moving in a straight line. Starting from rest, the time after which the particle returns to its starting position is

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The velocity-time graph of the particle moving along a straight line is shown. The rate of acceleration and deceleration is constant and it is equal to $5 \mathrm{m} {\mathrm{s}}^{-2}$. If average velocity during the motion is $20 \mathrm{m} {\mathrm{s}}^{-1}$, then find the value of $t$

An object moving with uniform acceleration has a velocity of $12.0 \mathrm{cm} {\mathrm{s}}^{-1}$ in the positive $x$ direction when its $x$ coordinate is $3.00 \mathrm{cm}$. If its $x$ coordinates $2.00 \mathrm{s}$ later is $-5 \mathrm{cm}$, what is its acceleration?

At a distance $L=400 \mathrm{m}$ from the traffic light brakes are applied to a locomotive moving at a velocity $v=54 \mathrm{km} {\mathrm{hr}}^{-1}$. Determine the position of the locomotive relative to the traffic light $1$ minute after the application of the brakes if its acceleration is $- 0.3 \mathrm{m} {\mathrm{s}}^{-2}$.

A body starts from rest, what is the ratio of the distances traveled by the body during the 4^th and 3^rd seconds?

A boy standing at the top of a tower of 20 m height drops a stone. Assuming  $g=10\mathrm{\hspace{0.17em}}\mathrm{m} {\mathrm{s}}^{-2}\hspace{0.17em},\hspace{0.17em}$ the velocity with which it hits the ground is

A particle has initial velocity $(3\widehat{i}+4\widehat{j})$ and has acceleration $(0.4\widehat{i}+0.3\widehat{j}).$ Its speed after 10 s is:

A ball is dropped from a high rise platform at, $t=0$ starting from rest. After $6 \mathrm{s}$ another ball is thrown downwards from the same platform with the speed $v$. The two balls meet at, $t=18 \mathrm{s}$. What is the value of $v$? (Take, $g=10 \mathrm{m} {\mathrm{s}}^{-2}$ )

A particle starts its motion from rest under the action of a constant force. If the distance covered in the first $10$ seconds is $S_1$ and that covered in the first $20$ seconds is  $S_2$, then:

A particle moves in a straight line with a constant acceleration. It changes its velocity from $10\mathrm{m} {\mathrm{s}}^{-1}$  to  $20\mathrm{m} {\mathrm{s}}^{-1}$ while passing through a distance $135 \mathrm{m}$ in $t$ seconds. The value of $t$ is:

The position $x$ of a particle with respect to time $t$ along $x$-axis is given by, $x=9t^2-t^3$ where, $x$ is in meters and $t$ is in seconds. What will be the position of this particle when it achieves maximum speed along the $+ve x$ direction?

Two bodies, $\mathrm{A}$ (of mass $1 \mathrm{kg}$) and $\mathrm{B}$ (of mass $3 \mathrm{kg}$), are dropped from heights of $16 \mathrm{m}$ and $25 \mathrm{m}$, respectively. The ratio of the times taken by them to reach the ground is

If a ball is thrown vertically upwards with speed u, the distance covered during the last t seconds of its ascent is